-3=x^2+6x-1

Solution for -3=x^2+6x-1 equation:

-3=x^2+6x-1

We move all terms to the left:

-3-(x^2+6x-1)=0

We get rid of parentheses

-x^2-6x+1-3=0

We add all the numbers together, and all the variables

-1x^2-6x-2=0

a = -1; b = -6; c = -2;
Δ = b2-4ac
Δ = -62-4·(-1)·(-2)
Δ = 28
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{28}=\sqrt{4*7}=\sqrt{4}*\sqrt{7}=2\sqrt{7}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-2\sqrt{7}}{2*-1}=\frac{6-2\sqrt{7}}{-2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+2\sqrt{7}}{2*-1}=\frac{6+2\sqrt{7}}{-2}
$